
c++ - What is "operator<<" called? - Stack Overflow
Apr 11, 2011 · I know the names of most of the operators but not sure what operator<< and operator>> are called. i.e. operator= () // the assignment operator operator== () // the equality of comparison
What does the |= operator mean in C++? - Stack Overflow
Nov 18, 2010 · What does the |= operator mean in C++?It is a bitwise OR compound assignment. In the same way as you can write x += y to mean x = x + y you can write x |= y to mean x = x | y, which …
C# 'or' operator? - Stack Overflow
Jan 18, 2014 · C# supports two boolean or operators: the single bar | and the double-bar ||. The difference is that | always checks both the left and right conditions, while || only checks the right-side …
What does the !! (double exclamation mark) operator do in JavaScript ...
I saw this code: this.vertical = vertical !== undefined ? !!vertical : this.vertical; It seems to be using !! as an operator, which I don't recognize. What does it do?
Understanding The Modulus Operator - Stack Overflow
Jul 8, 2013 · I understand the Modulus operator in terms of the following expression: 7 % 5 This would return 2 due to the fact that 5 goes into 7 once and then gives the 2 that is left over, however my …
sql - Oracle " (+)" Operator - Stack Overflow
Oct 26, 2010 · It should also be noted that even though the (+) works, Oracle recommends not using it: Oracle recommends that you use the FROM clause OUTER JOIN syntax rather than the Oracle join …
What is the Java ?: operator called and what does it do?
@DawoodibnKareem I think Michael deliberately included the in the italicisation of the ternary operator, and that's what he means is erroneous, not that ternary operator is erroneous. The ternary operator …
c# - Operator overloading ==, !=, Equals - Stack Overflow
Aug 23, 2014 · I've already gone through question I understand that, it is necessary to implement ==, != and Equals(). public class BOX { double height, length, breadth; // this is first one '==' ...
c++ - What is the difference between the dot (.) operator and ...
foo->bar() is the same as (*foo).bar(). The parenthesizes above are necessary because of the binding strength of the * and . operators. *foo.bar() wouldn't work because Dot (.) operator is evaluated first …
void setup/void drawでmissing operator,semicolon, or } のエラー表示 …
May 29, 2022 · void setup/void drawでmissing operator,semicolon, or } のエラー表示が消えなくて困っています。必要なものは書いてあるのうに思うのですがどこに何が必要なのでしょうか。教えて …